From bb2becdf7bae19bb80985e02f5f435767c9d7f44 Mon Sep 17 00:00:00 2001
From: songchunyi <2402265378@qq.com>
Date: Tue, 25 Aug 2026 03:41:16 +0000
Subject: [PATCH] =?UTF-8?q?=E5=88=A0=E9=99=A4=20=5Ffix=5Fdup.py?=
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---
 _fix_dup.py | 61 -----------------------------------------------------
 1 file changed, 61 deletions(-)
 delete mode 100644 _fix_dup.py

diff --git a/_fix_dup.py b/_fix_dup.py
deleted file mode 100644
index 159790c5..00000000
--- a/_fix_dup.py
+++ /dev/null
@@ -1,61 +0,0 @@
-import sys
-
-path = r'C:\Users\jsmbz\Documents\flutter-app-02\lib\features\home\presentation\widgets\map\testmap_pages.dart'
-
-with open(path, 'r', encoding='utf-8') as f:
-    lines = f.readlines()
-
-# 删除重复的 failMsg 声明和重复的检查逻辑 (行2402-2411，0索引为2401-2410)
-# 但行号可能因之前的编辑有偏移，用内容查找
-del_start = None
-del_end = None
-for i, line in enumerate(lines):
-    if 'debugPrint' in line and '创建设备任务失败' in line and 'failure' in line:
-        # 检查下一行是否是重复的 final failMsg
-        if i+1 < len(lines) and 'final failMsg = failure.toString();' in lines[i+1]:
-            # 找到了重复的起点
-            del_start = i  # debugPrint 行
-            # 找到这个重复块的结束：下一个 return; 之后的 }, 
-            for j in range(i+2, len(lines)):
-                if '// 其他失败' in lines[j] or (lines[j].strip() == 'return;' and 'taskCubit.clearCurrentTask();' in lines[j-1]):
-                    # 更精确：找到 "            return;" 且前一行是 taskCubit.clearCurrentTask
-                    if lines[j].strip() == 'return;':
-                        del_end = j + 1  # 包含 return; 行
-                        break
-            if del_end is None:
-                # 备选：找到下一个 '          },'  (fold 成功回调的开始)
-                for j in range(i+2, len(lines)):
-                    if lines[j].strip().startswith('},') and 'taskId' in lines[j+1]:
-                        del_end = j
-                        break
-            break
-
-if del_start is not None and del_end is not None:
-    print(f'Deleting lines {del_start+1} to {del_end}')
-    for k in range(del_start, del_end):
-        print(f'  DEL: L{k+1}: {lines[k].rstrip()}')
-    del lines[del_start:del_end]
-else:
-    print('Could not find duplicate block, checking for alternate pattern...')
-    # 备选：直接搜索两个 final failMsg 行
-    failmsg_lines = []
-    for i, line in enumerate(lines):
-        if 'final failMsg = failure.toString();' in line:
-            failmsg_lines.append(i)
-    print(f'failMsg lines: {[l+1 for l in failmsg_lines]}')
-    if len(failmsg_lines) >= 2:
-        # 删除第二个 failMsg 及它所属的整个重复检查块
-        second = failmsg_lines[1]
-        # 从第二个 failMsg 前一行 (debugPrint) 开始删
-        start = second - 1
-        # 找到这个 block 的结束
-        end = second + 8  # 大约8行后是这个重复块的结束
-        print(f'Alt: deleting lines {start+1} to {end}')
-        for k in range(start, min(end, len(lines))):
-            print(f'  DEL: L{k+1}: {lines[k].rstrip()}')
-        del lines[start:end]
-
-with open(path, 'w', encoding='utf-8', newline='') as f:
-    f.writelines(lines)
-
-print('DONE')